Java Certification Question 0045

What will happen when you attempt to compile and run the following code?

public class Sandys{

private int court;

public static void main(String argv[]){

Sandys s = new Sandys(99);

System.out.println(s.court);

}

Sandys(int ballcount){

court=ballcount;

}

}

1) Compile time error, the variable court is defined as private
2) Compile time error, s is not initialized when the System.out method is called
3) Compilation and execution with no output
4) Compilation and run with an output of 99

Answer 4:

4) Compilation and run with an output of 99

The fact that the variable court is declared as private does not stop the constructor from being able to initialise it.